Clone Graph
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization: Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node. As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
1.First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
2.Second node is labeled as 1. Connect node 1 to node 2.
3.Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
Tips:
先用bfs遍历取出所有节点存在Node里,然后map复制所有节点(不包括邻居),最后复制完成邻居。
可用BFS或DFS,我是用了BFS。先把所有点用BFS搞在ArrayList里,然后用map搞好,一一对应成新的,然后在把边搞了。
也有别的dfs和bfs的做法,都附上了。
Code:
解法1:自己的解法:
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) {
return node;
}
HashMap<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<>();
ArrayList<UndirectedGraphNode> nodes = bfs(node);
for (UndirectedGraphNode cur : nodes) {
map.put(cur, new UndirectedGraphNode(cur.label));
}
for (UndirectedGraphNode cur: nodes) {
UndirectedGraphNode newNode = map.get(cur);
for (UndirectedGraphNode neighbor : cur.neighbors) {
UndirectedGraphNode newNeighbor = map.get(neighbor);
newNode.neighbors.add(newNeighbor);
}
}
return map.get(node);
}
private ArrayList<UndirectedGraphNode> bfs(UndirectedGraphNode node) {
ArrayList<UndirectedGraphNode> result = new ArrayList<>();
Queue<UndirectedGraphNode> queue = new LinkedList<>();
HashSet<UndirectedGraphNode> set = new HashSet<UndirectedGraphNode>();
queue.add(node);
set.add(node);
while (!queue.isEmpty()) {
UndirectedGraphNode cur = queue.remove();
result.add(cur);
for (UndirectedGraphNode neighbor : cur.neighbors) {
if (!set.contains(neighbor)) {
queue.add(neighbor);
set.add(neighbor);
}
}
}
return result;
}
}
解法2/3:
private Map<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<UndirectedGraphNode, UndirectedGraphNode>();
// DFS
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
if (map.containsKey(node)) return map.get(node);
UndirectedGraphNode copy = new UndirectedGraphNode(node.label);
map.put(node, copy);
for (UndirectedGraphNode n : node.neighbors)
copy.neighbors.add(cloneGraph(n));
return copy;
}
// BFS
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
Queue<UndirectedGraphNode> q = new LinkedList<UndirectedGraphNode>();
q.add(node);
UndirectedGraphNode copy = new UndirectedGraphNode(node.label);
map.put(node, copy);
while (!q.isEmpty()) {
UndirectedGraphNode cur = q.poll();
for (UndirectedGraphNode neigh : cur.neighbors) {
if (map.containsKey(neigh)) map.get(cur).neighbors.add(map.get(neigh));
else {
UndirectedGraphNode neighCopy = new UndirectedGraphNode(neigh.label);
map.put(neigh, neighCopy);
map.get(cur).neighbors.add(neighCopy);
q.add(neigh);
}
}
}
return copy;
}