First Unique Character in a String

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.

Examples:

s = "leetcode"
return 0.

s = "loveleetcode",
return 2.

Note:You may assume the string contain only lowercase letters.

Tips：

用map扫两遍。

Code：

public class Solution {
    public int firstUniqChar(String s) {
        if (s == null || s.length() == 0) return -1;
        Map<Character, Integer> map = new HashMap<>();
        for (char c : s.toCharArray()) {
            map.put(c, map.getOrDefault(c, 0) + 1);
        }
        for (int i = 0; i < s.length(); i++) {
            if (map.get(s.charAt(i)) == 1) return i;
        }
        return -1;
    }
}