Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --
>
Returns -3.
minStack.pop();
minStack.top(); --
>
Returns 0.
minStack.getMin(); --
>
Returns -2.
Tips:
建立递减栈,将小于等于minStack栈顶元素都加入即可。
Code:
public class MinStack {
/** initialize your data structure here. */
Stack<Integer> stack;
Stack<Integer> minStack;
public MinStack() {
this.stack = new Stack<>();
this.minStack = new Stack<>();
}
public void push(int x) {
stack.push(x);
if (minStack.isEmpty() || x <= minStack.peek()) minStack.push(x);
}
public void pop() {
int x = stack.pop();
if (minStack.peek() == x) minStack.pop();
}
public int top() {
return stack.peek();
}
public int getMin() {
return minStack.peek();
}
}